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Exam : Oracle 1Z0-001
Title : INTRODUCTION TO ORACLE: SQL AND PL/SQL


1. Click on the EXHIBIT button and examine the structure of the DEPARTMENT and EMPLOYEE tables.
Evaluate this SQL statement:
CREATE INDEX emp_dept_id_idx
ON employee(dept_id);
Which result will the statement provide?
A. Store an index in the EMPLOYEE table.
B. Increase the chance of full table scans.
C. May reduce the amount of disk I/O for SELECT statements.
D. May reduce the amount of disk I/O for INSERT statements.
E. Override the unique index created when the FK relationship was defined.
Answer: C

2. The EMPLOYEE table contains these columns:
BONUSNUMBER(7,2)
DEPT_ID NUMBER(9)
There are 10 departments and each department has at least 1 employee. Bonus values are greater than 500; not all employees receive a bonus.
Evaluate this PL/SQL block:
DECLARE
v_bonusemployee.bonus%TYPE := 300;
BEGIN
UPDATE employee
SET bonus = bonus + v_bonus
WHERE dept_id IN (10, 20, 30);
COMMIT;
END;
What will be the result?
A. All employees will be given a 300 bonus.
B. A subset of employees will be given a 300 bonus.
C. All employees will be given a 300 increase in bonus.
D. A subset of employees will be given a 300 increase in bonus.
Answer: D

3. Click on the EXHIBIT button and examine the table instance chart for the patient table.
You need to create the patient_id_seq sequence to be used with the patient table's primary key column. The sequence should begin at 1000, have a maximum value of 999999999, never reuse any numbers, and increment by 1.
Which statement would you use to complete this task?
A. CREATE SEQUENCE patient_id_seq
START WITH 1000
MAXVALUE 999999999
NOCYCLE;
B. CREATE SEQUENCE patient_id_seq
START WITH 1000
MAXVALUE 999999999
STEP BY 1;
C. CREATE SEQUENCE patient_id_seq
ON patient (patient_id)
MINVALUE 1000
MAXVALUE 999999999
INCREMENT BY 1
NOCYCLE;
D. This task cannot be accomplished.
Answer: A

4. Given this executable section of a PL/SQL block:
BEGIN
FOR employee_record IN salary_cursor LOOP
employee_id_table(employee_id) :=
employee_record.last_name;
END LOOP;
CLOSE salary_cursor;
END;
Why does this section cause an error?
A. The cursor needs to be opened.
B. No FETCH statements were issued.
C. Terminating conditions are missing.
D. The cursor does not need to be closed.
Answer: D

5. The structure of the DEPT table is as follows:
Name Null? Type
------------------------------- -------- -------
DEPTNO NOT NULL NUMBER(2)
DNAME VARCHAR2(14)
LOC VARCHAR2(13)
Examine the code:
DECLARE
TYPE dept_record_type IS RECORD
(dno NUMBER,
name VARCHAR2(20));
dept_rec dept_record_type;
BEGIN
SELECT deptno, dname
INTO dept_rec
FROM dept
WHERE deptno = 10;
END;
Which statement displays the name of the selected department?
A. DBMS_OUTPUT.PUT_LINE(name);
B. DBMS_OUTPUT.PUT_LINE(dname);
C. DBMS_OUTPUT.PUT_LINE(dept_rec.name);
D. DBMS_OUTPUT.PUT_LINE(dept_rec.dname);
E. DBMS_OUTPUT.PUT_LINE(dept_rec(name));
Answer: C

6. Which should you do after each FETCH statement in a PL/SQL block?
A. Open the cursor.
B. Close the cursor.
C. Initialize the loop.
D. Test for rows using a cursor attribute.
Answer: D

7. You issue this command:
CREATE SYNONYM emp
FOR ed.employee;
Which task has been accomplished?
A. The need to qualify an object name with its schema was eliminated for user Ed.
B. The need to qualify an object name with its schema was eliminated for only you.
C. The need to qualify an object name with its schema was eliminated for all users.
D. The need to qualify an object name with its schema was eliminated for users with access.
Answer: B

8. Click on the EXHIBIT button and examine the table instance chart for the cars table.
Which SELECT statement will display style, color, and lot number for all cars based on the model entered at the prompt, regardless of case?
A. SELECT style, color, lot_no
FROM cars
WHERE model = UPPER('&model');
B. SELECT style, color, lot_no
FROM cars
WHERE model = '&model';
C. SELECT style, color, lot_no
FROM cars
WHERE UPPER(model) = UPPER('&model');
D. SELECT style, color, lot_no
FROM cars
WHERE UPPER(model) = '&model';
Answer: C